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KCET2015PhysicsElectrostatics

A spherical shell of radius ( 10 ~cm ) is carrying a charge ( q ). If the electric potential at distances ( 5 ) ( cm , 10 ~cm ) and ( 15 ~cm ) from the centre of the spherical shell is ( V₁, V₂ ) and ( V₃ ) respectively, then

Options

  1. A( V₁>V₂>V₃ )
  2. B( V₁ < V₂ < V₃ )
  3. C( V₁=V₂>V₃ )
  4. D( V₁=V₂ < V₃ )

Correct answer

C. ( V₁=V₂>V₃ )

Step-by-step solution

It is given, electric potential at ( 5 ~cm =V₁ ) electric potential at ( 10 ~cm =V₂ ) electric potential at ( 15 ~cm =V₃ ) We know potential inside a conductor is same everywhere, therefore electric potential at ( 5 ~cm ) and ( 10 ~cm ) distance will be same, that is, ( V₁=V₂ ) Now, electric potential is given as [ array l V= 1 4 ₀ q R V 1 R V₃>V₁=V₂ array ] Thus, electric potential at ( 5 ~cm , 10 ~cm ) and ( 15 ~cm ) are [ V₁=V₂>V₃ ]

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