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KCET2015PhysicsElectrostatics

A parallel plate capacitor is charged and then isolated. The effect of increasing the plate separation on charge, potential and capacitance respectively are

Options

  1. Aconstant, decreases, decreases
  2. Bincreases, decreases, decreases
  3. Cconstant, decreases, increases
  4. Dconstant, increases, decreases

Correct answer

D. constant, increases, decreases

Step-by-step solution

Given, parallel plate is charged and then isolated. Therefore, ( Q= ) constant. Now, capacitance is given as ( C= ₀ A d C 1 d ) So, if the separation between plates is increased then, C decreases. Also, we know ( Q=C V V= Q C V 1 C ) So, if ( C ) decreases then potential increases. Thus, on increasing the plate separation charge remains constant, potential increases and capacitance decreases.

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