KCET2015PhysicsElectrostatics
A proton beam enters a magnetic field of ( 10⁻⁴ ~Wb m⁻² ) normally. If the specific charge of the proton is ( 10¹¹ C kg ⁻¹ ) and its velocity is ( 10⁹ ~ms ⁻¹ ), then the radius of the circle described will be
Options
- A( 0.1 ~m )
- B( 10 ~m )
- C( 100 ~m )
- D( 1 ~m )
Correct answer
C. ( 100 ~m )
Step-by-step solution
Magnetic field ( B=10⁻⁴ ~W bm ⁻² ), charge ( q=10¹¹ Ck g⁻¹ ) velocity ( v=10⁹ ~ms ⁻¹ ) Now, radius of the circle described by proton is ( r= m v q B = v ( q m ) B = 10⁹ 10¹¹ 10⁻⁴ =10² ) Therefore, radius of circle is ( 100 ~m ).