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KCET2013PhysicsElectrostatics

A uniform electric field in the plane of the paper as shown. Here A, B, C and D are the ponits on the circle. V₁, V₂, V₃ and V₄ are the potentials at those points respectively. Then

Options

  1. AV_ A =V_ C , V_ B =V_ D
  2. BV_ A =V_ C , V_ B >V_ D
  3. CV_ A >V_ C , V_ B >V_ D
  4. DV_ A =V_ B , V_ C =V_ D

Correct answer

D. V_ A =V_ B , V_ C =V_ D

Step-by-step solution

The field is uniform in the plane of the paper. We know that in uniform electric field, the value of potentials is same for those points which are at equal distances. Therefore, V_ A =V_ B (Both points A and B lies on opposite sides on the circumference) and V_ C >V_ D (As point C lies earlier than point D on the circumference). V_ A =V_ B , V_ C >V_ D

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