In the uniform electric field of E =1 10⁴ NC ⁻¹ , an electron is accelerated from rest. The velocity of the electron when it has travelled a distance of 2 10⁻² ~m is nearly ( e m of electron 1.8 10⁻¹¹ C kg ⁻¹ )

Step-by-step solution

By work-energy theorem, aligned Work done by electric field =& array l Change in KE of electron array aligned or qE x= 1 2 mv ² or v= 2 q E x m aligned &= 2 1.8 10¹¹ 1 10⁴ 2 10⁻² &=8.5 10⁶ ~ms ⁻¹ aligned