KVPY2019ChemistryCoordination Compounds
For an octahedral complex MX 4 Y 2 ( M = a transition metal, X and Y are monodentate achiral ligands), the correct statement among the following is
Options
- AMX 4 Y 2 has 2 geometrical isomers, one of which is chiral
- BMX 4 Y 2 has 2 geometrical isomers both of which are achiral
- CMX 4 Y 2 has 4 geometrical isomers, all of which are achiral
- DMX 4 Y 2 has 4 geometrical isomers, two of which are chiral
Correct answer
B. MX 4 Y 2 has 2 geometrical isomers both of which are achiral
Step-by-step solution
Two geometrical isomers (cis and trans with respect to ligand Y ) are possible. The trans isomer has both centre of symmetry and several planes of symmetry. and, therefore it is achiral. The cis isomer has two planes of symmetry and, therefore it is also achiral.