For electroplating, 1.5 amp current is passed for 250 s through 250 mI . of 0.15 M solution of MSO ₄ . Only 85 % of the current was utilized for electrolysis. The molarity of MSO ₄ solution after electrolysis is closest to [Assume that the

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For electroplating, 1.5 amp current is passed for 250 s through 250 mI . of 0.15 M solution of MSO ₄ . Only 85 % of the current was utilized for electrolysis. The molarity of MSO ₄ solution after electrolysis is closest to [Assume that the volume of the solution remained constant]

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Correct answer: A. 0.14

No. of mole = i t 96500 v . f , n v . f = i t 96500 n = 1.5 250 96500 2 0.85 n =.00165 (deposited) n _ i = 250 .15 1000 =.0375 (initial mole) n _ left =.03585 (mole left) M _ left = .03585 .25 =0.143

For electroplating, 1.5 amp current is passed for 250 s through 250 mI . of 0.15 M solution of MSO ₄ . Only 85 % of the current was utilized for electrolysis. The molarity of MSO ₄ solution after electrolysis is closest to [Assume that the volume of the solution remained constant]

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