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KVPY2017ChemistryElectrochemistry

The limiting molar conductivities of the given electrolytes at 298 ~K follow the order array l [ ⁰ ( ~K ⁺ )=73.5, ⁰ ( Cl ⁻ )=76.3 . . ⁰ ( Ca ²⁺ )=119.0, ⁰ ( SO ₄²⁻ )=160.0 ~S ~cm ² ~mol ⁻¹ ] array

Options

  1. AKCl < CaCl ₂ < K ₂ SO ₄
  2. BKCl < K ₂ SO ₄ < CaCl ₂
  3. CK ₂ SO ₄ < CaCl ₂ < KCl
  4. DCaCl ₂ < K ₂ SO ₄ < KCl

Correct answer

A. KCl < CaCl ₂ < K ₂ SO ₄

Step-by-step solution

^ _ KCl =73.5+76.3=149.8 _ CaCl ₂ ^ =119+2 76.3=271.6 ^ _ K ₂ SO ₄ =2 73.5+160=307

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