Electrolysis of concentrated aqueous solution of NaCl results in

Step-by-step solution

The cathode half-reaction in the process is 2 H 2 O + 2 e - ⟶ H 2 + 2 OH - which increases OH - and, therefore pH and the anode half-reaction. 2 Cl - ⟶ Cl 2 + 2 e - does not produce or consume H + or OH - . Overall, the reaction can be written as 2 NaCl + 2 H 2 O ⟶ 2 NaOH + H 2 + Cl 2