KVPY2011ChemistryElectrochemistry
The standard Gibbs free energy change ( G ^ . in kJ mol ⁻¹ ), in a Daniel cell ( E _ cell ^ =1.1 ~V . ), when 2 moles of Zn ( s ) is oxidized at 298 ~K , is closest to
Options
- A-212.3
- B-106.2
- C-424.6
- D-53.1
Correct answer
C. -424.6
Step-by-step solution
Zn + Cu ⁺² Zn ⁺²+ Cu 2 Zn +2 Cu ⁺² 2 Zn ⁺²+2 Cu For 2 moles of Zn , n =4 G ^ =- nFE _ Cell ^ =-4 96500 1.1=-424.6 ~kJ