A closed 10   L vessel contains 1   L water gas 1 : 1 CO : H 2 and 9   L air ( 20 % O 2 by volume) at STP . The contents of the vessel are ignited. The number of moles of CO 2 , in the vessel is closest to :

Step-by-step solution

Water gas ( CO : H 2 is 1 : 1 ) = 1 litre Air = 9 litre 1 litre water gas at STP ⇒ 1 22 . 4 moles of gas at STP No. of moles of CO = 1 2 × 1 22 . 4 moles = No. of moles of CO 2 produced after ignition = 0 . 022