An organic compound contains 46 . 78 % of a halogen X . When 2 . 00   g of this compound is heated with fuming HNO 3 in the presence of AgNO 3 , 2 . 21   gAg X was formed. The halogen X is [Given : atomic weight of Ag = 108 ,   F = 19 , Cl = 355 Br = 80 , I = 127 ]

Step-by-step solution

Mass of AgX = 2 . 21   g Mass of X = 46 . 78 % of 2 . 00   g = 46 . 78 × 2 . 00 100 ≅ 0 . 94   g Mass of Ag in AgX must be 2 . 21 - 0 . 94   g = 1 . 27   g ∴ Number of moles of Ag = 1 . 27 108 which is also equal to number of moles of X . ∴ Atomic mass of X =  mass  ' n ' = 0 . 94 × 108 1 . 27 ≅ 80 ∴ The halogen must be bromine (Br).