In the following reaction, P gives two products Q and R each in 40 % yield. If the reaction is carried out with 420 mg of P , the reaction yields 108 . 8 mg of Q . The amount of R produced in the reaction is closest to

Step-by-step solution

Number of moles of P = 420 × 10 - 3 210 = 2 × 10 - 3 Number of moles of Q and R = 40 % of P = 40 100 × 2 × 10 - 3 = 8 × 10 - 4 mass of = 8 × 10 - 4 × 10 6 = 84 . 8 × 10 - 3 = 84 . 8 mg mass of = 8 × 10 - 4 × 136 = 108 . 8 × 10 - 3 = 108 . 8 mg which is Q . ∴ Mass of R = 84 . 8 mg