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KVPY2012PhysicsCapacitance

The capacitor of capacitance C in the circuit shown in fully charged initially. Resistance is R.- After the switch S is closed, the time taken to reduce the stored energy in the capacitor to half its initial value is

Options

  1. ARC / 2
  2. B2 RC in 2
  3. CRC 2
  4. DRCln 2 2

Correct answer

D. RCln 2 2

Step-by-step solution

Discharging - Q = Q ₀ e ^ -t / RC , U ^ = U 2 Q ₀ ² 2 C e ^ -2 t / RC = Q ₀ ² 2 C

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