An electrostatic field line leaves at an angle α from point charge q 1 and connects with point charge - q 2 at an angle β ( q 1 and q 2 are positive) see figure below. If q 2 = 3 2 q 1 and α = 30 ° , then

Step-by-step solution

Consider another symmetric field line below line joining centres of charges q 1 and q 2 In given situation, flux (field lines) leaving charge q 1 at a solid angle 2 α = flux terminating over charge q 2 at a solid angle 2 β . Clearly, in given situation We can say that, flux leaving charge q 1 through a cone of semi-vertical angle α = flux terminating on charge q 2 through a cone of semi-vertical angle β . To calculate flux, we first find flux through an elemental ring of base of cone and then we integrate to get to