The radius of a nucleus is given by r ₀ ~A ^ 1 / 3 where r ₀=1.3 10⁻¹⁵ ~m and A is the mass number of the nucleus, the Lead nucleus has A =206 . the electrostatic force between two protons in this nucleus is approximately

Step-by-step solution

aligned r = r ₀ ~A ^ 1 / 3 & r ₀=1.3 10⁻¹⁵ & ~F = 1 4 ₀ q ₁ q ₂ r ² aligned F= 9 10⁹ 1.6 10⁻¹⁹ 1.6 10⁻¹⁹ r ₀² ~A ^ 2 / 3 ~F = 9 10⁹ 1.6 10⁻¹⁹ 1.6 10⁻¹⁹ (1.3)² 10⁻³⁰ (206)^ 2 / 3 = 23.04 10³⁹ 10⁻³⁸ (1.69) 34.81 = 23.04 10 1.69 34.81 =3.91 Newton =0.039 10² Ans .( A )