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KVPY2018PhysicsElectrostatics

In a particle accelerator, a current of 500   μ A is carried by a proton beam in which each proton has a speed of 3 × 10 7   m / s . The cross-sectional area of the beam is 1 . 50   m m 2 . The charge density in this beam (in C / m 3 is close to

Options

  1. A10 - 8
  2. B10 - 7
  3. C10 - 6
  4. D10 - 5

Correct answer

D. 10 - 5

Step-by-step solution

If Q is charge contained in L length of beam of area A , then L × A × ρ = Q where, ρ = charge density of beam. So ,    ρ = Q L × A = Q / t L / t × A = I v × A = 500 × 10 - 6 3 × 10 7 × 1 . 50 × 10 - 6 = 5 3 × 1 . 5 × 10 - 5 = 11 × 10 - 5   C m - 3

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