KVPY2010PhysicsElectrostatics
Two identical particles of mass ' m ' and charge q are shot at each other from a very great distance with an initial speed v . The distance of closest approach of these charges is-
Options
- Aq ² 8 ₀ mv ²
- Bq ² 4 ₀ mv ²
- Cq ² 2 ₀ mv ²
- D0
Correct answer
B. q ² 4 ₀ mv ²
Step-by-step solution
Using law of conservation of mechanical energy Initial K.E. = Final P.E. 1 2 mv ²+ 1 2 mv ²= kq ² r r = q ² 4 ₀ mv ²