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AIIMS 201827 May
Exam
AIIMS
Year
2018
Date
27 May
Subject
Chemistry
Chapter
Chemical Kinetics

AIIMS 2018 · 27 May · Chemistry · Chemical Kinetics

Which option is valid for a zero order reaction?

Which option is valid for a zero order reaction?

Options

  1. At3/4=32t1/2t_{3/4}=\frac{3}{2} t_{1/2}
  2. Bt1/2=42t3/4t_{1/2}=\frac{4}{2} t_{3/4}
  3. Ct1/2=2t3/4t_{1/2}=2 t_{3/4}
  4. Dt3/4=(t1/2)2t_{3/4}=\left(t_{1/2}\right)^2

Correct answer

A. t3/4=32t1/2t_{3/4}=\frac{3}{2} t_{1/2}

Step-by-step solution

For a zero order reaction, A=[A]0−ktA=[A]_0-k t t1/2=[A]02k;t3/4=32[A]02k∴t3/4t1/2=32t_{1/2}=\frac{[A]_0}{2 k} ; t_{3/4}=\frac{3}{2} \frac{[A]_0}{2 k} \therefore \frac{t_{3/4}}{t_{1/2}}=\frac{3}{2}
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