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Manipal MET2015ChemistryChemical Kinetics

For the two gaseous reactions, following data aligned & A B ; k₁=10¹⁰ e^ -20 ; 000 / T & C D ; k₂=10¹² e^ -24,606 / T aligned the temperature at which k₁ becomes equal to k₂ is

Options

  1. A400 K
  2. B1000 K
  3. C800 K
  4. D1500 K

Correct answer

B. 1000 K

Step-by-step solution

Given _ k₁=10¹⁰ e^ -20,000 / T aligned & k₂=10¹² e^ -24,606 / T & k₁=k₂ 10¹⁰ e^ -20,000 / T =10¹² e^ -24,606 / T aligned e^ - 20,000 T + 24606 T =10^2e^ 4,606 T =10^2 On taking log both sides, gathered 4.606 2.303 T = 10^2 2 10 T= 4606 2.303 T= 4606 2.303 2 = 4606 4.606 =1000 ~K gathered

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