Manipal MET2023ChemistryElectrochemistry
Value of E₂^0 is in the given diagram (ignore -ve sign)
Correct answer
0.77
Step-by-step solution
G₃= G₁+ G₁n₃ F E₃^ =n₁ F E₁^ +n₂ F E₂^ 3 0.036=2 0.439+1 E₂^ E₂^ =0.108-0.878=-0.77 ~V
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0.77
G₃= G₁+ G₁n₃ F E₃^ =n₁ F E₁^ +n₂ F E₂^ 3 0.036=2 0.439+1 E₂^ E₂^ =0.108-0.878=-0.77 ~V