Manipal MET2014ChemistryElectrochemistry
What is the cell potential (standard emf, E^0 ) for the reaction below? aligned & [E^0 ( Fe ²⁺(a q) Fe )=0.44 ~V . and & .E^0 ( O ₂(g) / H ₂ O / OH ⁻ )=+0.4 ~V ] & 2 Fe (s)+ O ₂(g)+2 H ₂ O (l) 2 Fe ²⁺(a q) aligned +4 OH ⁻(a q)
Options
- AE_ cell ^0=-0.48 ~V
- BE_ cell ^0=-0.04 ~V
- CE_ cell ^0=+0.84 ~V
- DE_ cell ^0=+1.28 ~V
Correct answer
C. E_ cell ^0=+0.84 ~V
Step-by-step solution
aligned E_ cell ^0 & =E_ cathode ^0-E_ anode ^0 & =0.40-(-0.44)=0.84 ~V aligned