A flask contains 98 mg of H ₂ SO ₄ . If 3.01 10²⁰ molecules of H ₂ SO ₄ are removed from the flask, the number of moles of H ₂ SO ₄ remained in flask is ( N =6.02 10²³ )

Step-by-step solution

Weight of H ₂ SO ₄(W)=98 mg =98 10⁻³ ~g [1 mg =10⁻³ ~g ] No. of mole in flask ( n ₁ )= 98 10⁻³ 98 =10⁻³ mole No. of mole removed from the flask (n₂ )= 3.01 10²⁰ 6.023 10²³ = 1 2 10⁻³ Remaining no. of moles in the flask ( n ₁- n ₂ ) aligned & =1 10⁻³- 1 2 10⁻³ & =0.5 10⁻³ & =5 10⁻⁴ ~mole aligned