0.1 mole of potassium permanganate was heated at 300^ C . What is the weight (ing) of the residue? ( Mn =55 u ; K =39 u ; O =16 u )

Step-by-step solution

2 KMnO ₄ 300^ C K ₂ MnO ₄+ MnO ₂ _ Solid residue + O ₂ Molecular weight of KMnO ₄=158 u Mole =0.1 aligned & Weight = Molecular weight mole & =0.1 158 & Weight of Total KMnO ₄=15.8 ~g & array l After heat O ₂ will evolved array & aligned Weight of O ₂= mole molecular weight =0.1 16 aligned & aligned & 1.6 ~g aligned & aligned Weight of Residue & =15.8-1.6 & =14.2 ~g aligned aligned