At STP ' x ' g of a metal hydrogen carbonate ( MHCO ₃ ) (molar mass 84 ~g ~mol ⁻¹ ) on heating gives CO ₂ , which can completely react with 0.2 moles of MOH (molar mass 40 g mol ⁻¹ ) to give MHCO ₃ . The value of ' x ' is

Step-by-step solution

Given, 0.2 moles of MOH reacts completely with CO ₂ CO ₂+ MOH M HCO ₃0.2 0.2 moles moles Now, 2 MHCO ₃ M ₂ CO ₃+ CO ₂+ H ₂ O 1 mole of CO ₂ is obtained from 2 moles of MHCO ₃ 0.2 mole of CO ₂ will be obtain from =2 0.2=0.4 mole of MHCO ₃ Hence, amount ' x ' =0.4 84=33.6 ~g