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AP EAMCET202318 May 2023Morning ShiftChemistrySome Basic Concepts of ChemistryActual

The vapors of 1 ~g of an element occupy 2.5625 ~L exerting a pressure of 0.5 ~atm at 1000 ~K . What is the molar mass (in g mol ⁻¹ ) of the element? (Assume vapors follow ideal gas equation Given R =0.082 ~L ~atm ~mol ⁻¹ ~K ⁻¹ )

Options

  1. A64
  2. B16
  3. C32
  4. D128

Correct answer

A. 64

Step-by-step solution

PV = nRT = m M RT M = mRT PV = (1)(0.082)(1000) (0.5)(2.5625) =64 ~g ~mol ⁻¹ .

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