One mole H ₂ O ( g ) and one mole CO ( g ) are taken in 1 ~L flask and heated to 725 ~K . At equilibrium, 40 % (by mass) of water reacted with CO ( g ) as follows. H ₂ O ( g )+ CO ( g ) H ₂( ~g )+ CO ₂( ~g ) Its K_p value is

Step-by-step solution

aligned & (b) K _ p = K _ c ( RT )^ n _ g & H ₂ O ( g )+ CO ( g ) H ₂( ~g )+ CO ₂( ~g ) & n _ g =(1+1)-(1+1)=0 & K _ p = K _ c . aligned Now, 40 % of mass of water reacted with CO. =0.4 array |c|c|c|c|c| & H ₂ O & CO & H ₂ & CO ₂ Initial moles & 1.0 & 1.0 & 0.0 & 0.0 At equilibrium & array c 1-0.4 =0.6 array & array c 1-0.4 =0.6 array & 0.4 & 0.4 array Thus, [ H ₂ O ]= 0.6 1.0 =0.6 M ,[ CO ]=0.6 M , aligned & [ H ₂ ]=0.4 M , [ CO ₂ ]=0.4 M & K _ C = [ H ₂ ] [ CO ₂ ] [ H ₂ O ][ CO ] = (0.4)(0.4) (0.6)(0.6) =0.444 al