Manipal MET2022ChemistrySome Basic Concepts of Chemistry
Arrange the following in increasing order of the volume (in L) occupied by them at STP (i) 1.5 moles of CO ₂ (ii) 14 g of N ₂ (iii) 10²¹ molecules of oxygen
Options
- A(iii) (ii) (i)
- B(i) (ii) (iii)
- C(ii) (i) (iii)
- D(i) (iii) (ii)
Correct answer
A. (iii) (ii) (i)
Step-by-step solution
(i) Volume occupied by 1 mole of CO ₂=22.4 ~L Volume occupied by 1.5 moles of CO ₂ aligned & =1.5 22.4 & =33.6 ~L aligned (ii) Given, mass of nitrogen (m)=14 ~g Molar mass of N ₂(w)=28 ~g Number of moles of N ₂= m w = 14 28 = 1 2 =0.5 ~mole Volume occupied by 1 mole of N ₂ at STP =22.4 ~L Volume occupied by 0.5 mole of N ₂ at STP aligned & =0.5 22.4 & =11.2 ~L aligned (iii) Given, number of molecules of O ₂=10²¹ Number of molecules of O ₂ in 1 mole aligned & =6.022 10²³ molecules Number of moles & = 10²¹ 6.022 10²³