Manipal MET2017ChemistrySome Basic Concepts of Chemistry
The mass of CaCO ₃ required to react with 25 mL of 0.75 M HCl is
Options
- A0.94 g
- B9.4 g
- C0.094 g
- D0.49 g
Correct answer
A. 0.94 g
Step-by-step solution
gathered CaCO ₃+2 HCl CaCl ₂+ CO ₂+ H ₂ O 25 ~mL of 0.75 M HCl = 25 1000 0.75=0.01875 ~mol gathered aligned & Moles of CaCO ₃ required = moles of HCl 2 & = 0.01875 2 =9.375 10⁻³ ~mol aligned aligned & Mass of CaCO ₃ required & =9.375 10⁻³ ~mol 100 ~g ~mol ⁻¹ & =0.9375 ~g =0.94 ~g aligned