How many grams of Mg is required to completely reduce 100 ml ,   0 . 1 M   NO 3 - solution using the following reaction NO 3 - + Mg ⟶ Mg 2 + + NH 3

Step-by-step solution

Given reaction NO 3 - + 5 + Mg 0 ⟶ Mg 2 + + 2 + N - 3 H 3 In this redox reaction oxidation state of N is changing from + 5   to   - 3 . So, n-factor for the NO 3 - will be 8 . And for the Mg it will be 2 . Now according to Law of equivalent, Number of equivalent of both should be equal. Eq .   of   NO 3 -   =   Eq .   of   Mg n - factor × M × V   =   n - factor × Mass   of   Mg Molar   mass 8 × 0 . 1 × 0 . 1 L   =