For formation of 3.40 ~g of ammonia gas, what volumes of hydrogen gas and nitrogen gas, respectively are required at NTP conditions?

Step-by-step solution

array ccc (c) N ₂ & +3 H ₂ & 1 ~V NH ₃ 22.4 ~L & 22.4 3 & 2 ~V =224 ~L & =67.2 ~L & =44.8 ~L array According to Gay-Lussac's law, 3 volumes of H ₂ will give 2 vol. of NH ₃ . 67.2 ~L of H ₂ will give = 2 67.2 3 =44.8 ~L of NH ₃ At the same time, 3 vol. of H ₂ will react =1 vol. of N ₂ . aligned 67.2 ~L of H ₂ will react & = 1 3 67.2 ~L of N ₂ & =224 ~L of N ₂ aligned 67.2 L of H ₂ and 22.4 ~L of N ₂ are required to form 34 ~g of NH ₃ . So, for 3.4 ~g of NH ₃ 6.72 L and 2.24 ~L of H ₂ and N ₂ gas are required respect