100 ~mL of 0.2 M acetic acid is completely neutralised using a standard solution of NaOH . The volume of ethane obtained at STP after complete electrolysis of the resulting solution is

Step-by-step solution

Given moles of acetic acid array r = 0.2 100 1000 =0.02 moles 2 CH ₃ COOH C ₂ H ₆+2 CO ₂+ H ₂ array 2 moles of CH ₃ COOH gives 1 mole of ethane =22.4 ~L 0.02 moles of CH ₃ COOH will give ethane = 22.4 0.02 2 =0.224 ~L 0.224 ~L of ethane is obtained.