If 500 ml of CaCl 2 solution contains 3 . 01 × 10 22 chloride ions, molarity of the solution will be

Step-by-step solution

CaCl 2 solution has the two mole of chloride ion. By applying the mole-mole analysis, The number of molecules of chloride ions = 3 . 01 × 10 22 2 Mole of chloride ion = Number   of   molecules N A = 3 . 01 × 10 22 2 × 6 . 02 × 10 23 = 0 . 025   mol Molarity of solution = Number   of   moles   of   solute Volume   of   solution   in   ml × 1000 Number of moles of solute = 0 . 025   mol Volume of solution = 500   ml Molarity of