If 0 . 2 moles of sulphuric acid is poured in to 250 ml of water, calculate the concentration of the solution?

Step-by-step solution

We know that concentration is dependent on the number of moles of solute and the volume of solution in L and it is given by: Molarity = number   of   moles   of   solute volume   of   solution   in   L Here, n = 0 . 2 , V = 250   ml Therefore, Molarity = 0 . 2 1 × 4 = 0 . 8   M Hence, concentration of 250   ml of water containing 0 . 2 moles of sulphuric acid will be 0 . 8   M