Calculate the amount of NO ₂ required for producing 4 ~g moles of HNO ₃ as per the chemical reaction, 3 NO ₂+ H ₂ O 2 HNO ₃+ NO . Given, the gram molecular weights of di-nitrogen and di-oxygen gases are 28 ~g and 32 ~g respectively.

Step-by-step solution

4 ~g mole HNO ₃=4 63=252 ~g HNO ₃ (3 46=138 ~g ) 3 NO ₂+ H ₂ O (2 63=126 ~g ) 2 HNO ₃+ NO According to the balance chemical reaction 126 ~g HNO ₃ produced by 138 ~g NO ₂ 252 ~g HNO ₃ will be produced by 126 138 252=276 ~g NO ₂ Hence, the correct option is (1).