Manipal MET2010PhysicsAlternating Current
The peak value of an alternating emf E given by E=E₀ t is 10 V and its frequency is 50 Hz . At a time t= 1 600 ~s , the instantaneous value of the emf is
Options
- A10 V
- B5 3 ~V
- C5 V
- D1 V
Correct answer
B. 5 3 ~V
Step-by-step solution
aligned E=E₀ t & =10 (2 f t) & =10 (2 50 1 600 ) aligned =10 ( 6 )=10 3 2 =5 3 ~V