Manipal MET2024PhysicsAtomic Physics
If an electron in n=4 orbit of hydrogen atom jumps down to n=3 orbit, the amount of energy released and the wavelength of radiation emitted are
Options
- A0.66 eV , 1.88 10⁻⁶ ~m
- B1.89 eV , 1.98 10⁻⁷ ~m
- C0.29 eV , 1.78 10⁻⁵ ~m
- D0.98 eV , 0.93 10⁻⁶ ~m
Correct answer
A. 0.66 eV , 1.88 10⁻⁶ ~m
Step-by-step solution
aligned E & = -13.6 n^2 eV E₄-E₃ & =13.6 [ 1 (3)^2 - 1 (4)^2 ] aligned aligned & =13.6 [ 7 144 ] eV =0.66 eV & = 1 R [ 1 (3)^2 - 1 (4)^2 ] = 144 1.09 10^7 7 ~m & =1.88 10⁻⁶ ~m aligned