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Manipal MET2020PhysicsCapacitance

When a dielectric slab is introduced between the plates of a capacitor connected to a battery, then

Options

  1. Acharge on capacitor increases
  2. Bpotential difference across the capacitor increases
  3. Cenergy stored increases
  4. Dcapacity remains the same

Correct answer

A. charge on capacitor increases

Step-by-step solution

As the battery remains connected. potential difference (V) of the capacitor remains constant. Suppose dielectric of dielectric constant K is introduced between the plates. Now, capcitance of the capacitor is C^ =K C₀ where, C₀ is original capacitance. Initial energy stored in the capacitor U_i= 1 2 C₀ V^2 Final energy stored in the capacitor U_t= 1 2 C^ V^2= 1 2 (K C₀ ) V^2 Clearly, U_t U_i =K 1 U_f U_i As, Q=C V V remains constant and C increases. Q increases.

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