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Manipal MET2017PhysicsCapacitance

Two capacitors, one 4 pF and the other 6 pF , connected in parallel, are charged by a 100 V battery. The energy stored in the capacitors is

Options

  1. A12 10⁻⁸ ~J
  2. B2.4 10⁻⁸ ~J
  3. C5.0 10⁻⁸ ~J
  4. D1.2 10⁻⁶ ~J

Correct answer

C. 5.0 10⁻⁸ ~J

Step-by-step solution

The energy stored in capacitor is given by E= 1 2 C V^2 Resultant capacitance aligned C^ & =C₁+C₂=4+6=10 pF E & = 1 2 10 10⁻¹² (100)^2 (1 pF =10⁻¹² ~F ) & =5 10⁻⁸ ~J aligned

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