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Manipal MET2011PhysicsCapacitance

An alternating voltage E=200 2 (100 t) V is connected to a 1 ~F capacitor through an AC ammeter. The reading of ammeter is

Options

  1. A10 mA
  2. B20 mA
  3. C40 mA
  4. D80 mA

Correct answer

B. 20 mA

Step-by-step solution

Given E=200 2 (100 t) ..(i) Comparing Eq. (i) with E=E₀ t Peak voltage E₀=200 2 , =100C=1 ~F =1 10⁻⁶ ~F Reáding of ammeter, i= E_ rms X_C aligned & = E₀ _C 2 = E_ rms 1 / C = E₀ C 2 & = 200 2 100 1 10⁻⁶ 2 & =20 10⁻³ ~A & =20 ~mA aligned

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