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Manipal MET2023PhysicsCapacitance

A charged capacitor when filled with a dielectric K=3 has charge Q₀ , voltage V₀ and field E₀ . If the dielectric is replaced with another one having K=9 , the new values of charge voltage and field will be respectively

Options

  1. A3 Q₀, 3 V₀, 3 E₀
  2. BQ₀, 3 V₀, 3 E₀
  3. CQ₀, V₀ 3 , 3 E₀
  4. DQ₀, V₀ 3 , E₀ 3

Correct answer

D. Q₀, V₀ 3 , E₀ 3

Step-by-step solution

When charging battery is disconnected then charge remains constant, V becomes 1 / K times and E becomes 1 / K times. So, new value of charge is Q₀ . New value of V= V₀ 3 9 = V₀ 3 New value of E= E₀ 3 9 = E₀ 3

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