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Manipal MET2018PhysicsCurrent Electricity

In a potentiometer experiment two cells of emf E₁ and E₂ are used in series and in conjunction and the balancing length is found to be 58 cm of the wire. If the polarity of E₂ is reversed, then the balancing length becomes 29 cm . The ratio E₁ E₂ of the emfs of the two cells is

Options

  1. A1:1
  2. B2:1
  3. C3:1
  4. D4:1

Correct answer

C. 3:1

Step-by-step solution

E₁+E₂=k 58 (i)E₁-E₂=k 29 (i i) E₁+E₂ E₁-E₂ =2 E₁ E₂ = 3 1

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