Manipal MET2017PhysicsCurrent Electricity
An electron at rest is accelerated through a potential difference of 200 V . If the electron acquires a velocity of 8.4 10^8 ~cm / s , its e m ratio is
Options
- A1.76 10¹¹ C / kg
- B2.5 10^9 C / kg
- C1.5 10^5 C / kg
- D9.8 10^3 C / kg
Correct answer
A. 1.76 10¹¹ C / kg
Step-by-step solution
aligned & 1 2 m v^2=e V & e m = v^2 2 V aligned Given, V=200 volt, v=8.4 10^8 ~cm / s =8.4 10^6 ~m / s e m = (8.4 10^6 )^2 2 200 =1.76 10¹¹ C / kg