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Manipal MET2015PhysicsCurrent Electricity

We have a galvanometer of resistance 25 . It is shunted by 2.5 wire. The part of the total current that flows through the galvanometer is given as

Options

  1. Ai i₀ = 4 11
  2. Bi i₀ = 3 11
  3. Ci i₀ = 2 10
  4. Di i₀ = 1 11

Correct answer

D. i i₀ = 1 11

Step-by-step solution

When a galvanometer is connected to the shunt resistance, then we have potential drop across the galvanometer = potential drop across the shunt i.e. i G= (i-i₀ ) S ...(i) Here, i= current through the galvanometer G= resistance of the galvanometer i₀= current through the shunt resistance S= shunt resistance From Eq. (i), we have the part of the total current that flows through the galvanometer is i i₀ = S G+S Substituting, S=2.5 , G=25 , we get i i₀ = 1 11

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