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Manipal MET2012PhysicsCurrent Electricity

If 1 A of current is passed through CuSO ₄ solution for 10 s , the number of copper atoms deposite at the cathode will be about

Options

  1. A1.6 10²⁰
  2. B8 10¹⁹
  3. C3.1 10¹⁹
  4. D6.2 10¹⁹

Correct answer

C. 3.1 10¹⁹

Step-by-step solution

Number of Cu ions liberated is array rl n & = I t e( valence electron) n & = 1 10 1.6 10⁻¹⁹ 2 n & n=3.125 10¹⁹ n & 3.1 10¹⁹ array

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