Manipal MET2011PhysicsCurrent Electricity
A 10 ~F capacitor is charged to a potential difference of 50 V and is connected to another uncharged capacitor in parallel. Now the common potential difference becomes 20 V . The capacitance of second capacitor is
Options
- A10 ~F
- B20 ~F
- C30 ~F
- D15 ~F
Correct answer
D. 15 ~F
Step-by-step solution
C₁=10 ~F , V=50 ~V Charge on first capacitor aligned q & =C₁ V & =10 50=500 C aligned Common potential V= total charge total capacitance 20= 500 C₁+C₂ or 20= 500 10+C₂ or C₂=15 ~F