Manipal MET2010PhysicsCurrent Electricity
A battery of emf 10 V is connected to resistance as shown in figure. The potential difference V_A-V_B between the points A and B is
Options
- A-2 ~V
- B2 V
- C5 V
- D20 11 ~V
Correct answer
B. 2 V
Step-by-step solution
R_ eq =5 , current i= 10 5 =2 ~A and current in each branch =1 ~A . Potential difference between C and A , V_C-V_A=1 1=1 ~V ...(i) Potential difference between C and BV_C-V_B=1 3=3 V...(ii) On solving Eqs. (i) and (ii) we get V_A-V_B=2 ~V