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Manipal MET2013PhysicsElectromagnetic Induction

An inductor is connected to a battary through a switch induced emf is a when the switch is pressed and e₂ when the switch is opened. Then

Options

  1. Ae₁=e₂
  2. Be₁ e₂
  3. Ce₁ e₂
  4. De₁ e₂

Correct answer

A. e₁=e₂

Step-by-step solution

When the switch is closed, the current grows in the circuit but due to self-inductance of the switch inductor the growth is slow. On disclosing the switch the current suddenly decrease to zero on account of the infinite resistance of the circuit. Thus, rate cf growth of the current is lower as compared to the rate of decays

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