Manipal MET2015PhysicsElectromagnetic Induction
Two coils have mutual inductance 0.005 H . The current changes in the first coil according to equation I=I₀ t , where I₀=10 ~A and =100 rad / s . The maximum value of emf in the second coil is
Options
- A12
- B8
- C5
- D2
Correct answer
C. 5
Step-by-step solution
The instantaneous current in the AC circuit is given by I=I₀ t aligned & d I d t = d d t (I₀ t ) & d I d t = (I₀ t ) aligned Substituting I₀=10 ~A , =100 aligned (100 ) & =1, we get d I d t & =1000 aligned Hence, induced emf is given by E=M d I d t On putting M=0.005 H , d I d t =1000 , we get E=(5 ) V