Manipal MET2017PhysicsElectrostatics
A charged particle of mass m and charge q is released from rest in a electric field of magnitude E . The kinetic energy of the particle after t second is
Options
- Aq E t 2 m
- Bq^2 E^2 t 2 m
- Cq^2 E^2 t^2 m
- Dq^2 E^2 t^2 2 m
Correct answer
D. q^2 E^2 t^2 2 m
Step-by-step solution
Force on a particle with charge q in electric field E is aligned F & =q E=m a a & = q E m aligned here a= v t v t = q E m v= q E t m Also, kinetic energy is due to velocity (v) is K= 1 2 m v^2= 1 2 m ( q E t m )^2= q^2 E^2 t^2 2 m